Proof using continuous f(x+y)=f(x)+f(y)

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Homework Statement



Let f be a continuous function lR (all real numbers) --> lR such that f(x+y) = f(x) + f (y) for x, y in lR.
prove that f(n) = n*f(1) for all n in lN (all natural numbers)

Homework Equations



f is continuous

also note and prove that f(0) = 0

The Attempt at a Solution



Edit:
I figured out the general proof using induction, assuming that the base case f(0) is true:

Assuming f(n) = nf(1), prove that f(n+1) = (n+1)f(1):

we know f(x+y) =f(x) + f (y)
so f(n+1) =f(n) + f (1)
and according to inductive hypothesis, f(n) = nf(1)
s0 f(n) + f (1)
= nf(1) + f (1)
=(n+1)f(1).

But I still don't understand why the base case f(0) = 0 is true..?
 
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f(0) = f(0 + 0) = f(0) + f(0) => f(0) = 0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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