Proofing Logarithms: a^(log(b))=b^(log(a))

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Does anyone know how to proof the following:

a^(log(b))=b^(log(a))

for a,b>0
 
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Let x = alog b and y = blog a

Using the rules of logarithms, show that log x = log y, hence that alog b = blog a
 
thanks
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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