Propelling force due to an orifice

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The discussion revolves around calculating the propelling force on a trolley due to water flowing from an orifice in a tank. The problem states that the tank is 1.5m high with an orifice diameter of 0.1m and a coefficient of discharge of 0.60. The initial attempt at calculating the force resulted in an incorrect value of 110.35N, prompting questions about the correct approach and the velocity of flow through the orifice. The correct velocity is determined to be 4.84 m/s using the formula √(2gh). The final answer for the propelling force is given as 67.39N, indicating a need for clarity in the calculations.
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Homework Statement


A tank 1.5m high stands on a trolley and is full of water .it has an orifice of diameter 0.1m at 0.3m from the bottom of the tank.if the orifice is suddenly opened coefficient of discharge of the orifice is 0.60, then find propelling force on the trolley.
Ans: 67.39N

Homework Equations


F=c⋅ρ⋅A⋅v^2

The Attempt at a Solution


It looks like a simple problem based on Newton's third law of motion where the propelling force on the trolley must be equal to the change in momentum of the liquid jet coming out of the orfice.

thus F= 0.6X10^3X (Π/4)0.1^2X2X9.8X1.2
=110.35
which is not correct.

I am not getting what's wrong with my approach.
 
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What is the velocity of the flow through the orifice ?
 
Nidum said:
What is the velocity of the flow through the orifice ? Why is this relevant ?
velocity of the flow will be: √(2gh)=√(2X9.8X1.2) =4.84
didn't understand next part
 
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