- #1
sara_87
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Question:
Let f: A -> B be a bijective function. Prove that
f o f^(-1) = IB
(IB = I lowercase B )
Answer:
Let x be an arbitrary element in the set A and f(x)=y . Therefore x is in A because f: A -> B.
f o f^(-1)
=f(f^(-1) (x))
and that's as far as i got
any help would be appreciated
thank you
Let f: A -> B be a bijective function. Prove that
f o f^(-1) = IB
(IB = I lowercase B )
Answer:
Let x be an arbitrary element in the set A and f(x)=y . Therefore x is in A because f: A -> B.
f o f^(-1)
=f(f^(-1) (x))
and that's as far as i got
any help would be appreciated
thank you