Properties of derivatives of a wavefunction?

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SUMMARY

The discussion centers on the properties of derivatives of a wavefunction as presented in Griffiths' introductory Quantum Mechanics (QM) textbook. The integral equation discussed, \(\int_{-\infty} ^{\infty} \frac{\partial }{\partial x}\left[ \frac{\partial \Psi ^{*}}{\partial x} \frac{\partial \Psi}{\partial x} - \Psi ^{*} \frac{\partial ^2 \Psi }{\partial x^2} \right] dx = 0\), highlights the importance of boundary conditions in QM. It is established that while the wavefunction approaches zero at the boundaries, the derivatives must also approach zero smoothly to maintain continuity, particularly in scenarios like an infinite potential well.

PREREQUISITES
  • Understanding of Quantum Mechanics principles, particularly wavefunctions
  • Familiarity with Griffiths' "Introduction to Quantum Mechanics" textbook
  • Knowledge of calculus, specifically integration and differentiation
  • Concept of boundary conditions in quantum systems
NEXT STEPS
  • Study the implications of boundary conditions in quantum mechanics
  • Explore the mathematical derivation of the integral equation presented
  • Learn about the continuity of wavefunctions and their derivatives in quantum systems
  • Investigate the properties of wavefunctions in infinite potential wells
USEFUL FOR

Students of Quantum Mechanics, physicists, and anyone interested in the mathematical foundations of wavefunctions and their derivatives in quantum systems.

Torboll1
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Hi!

I'm currently re-reading Griffiths introductory QM book and plan to do most of the exercises. I got stuck on one problem and had to look for some hints and found two solutions that both claim that:

[tex]\int_{-\infty} ^{\infty} \frac{\partial }{\partial x}\left[ \frac{\partial \Psi ^{*}}{\partial x} \frac{\partial \Psi}{\partial x} - \Psi ^{*} \frac{\partial ^2 \Psi }{\partial x^2} \right] dx = 0 .[/tex]

What Griffiths really push is that the wave function approaches zero at the boundaries but he states nothing about the derivatives (other than that they need be continuous). Can someone help me understand this?
 
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The derivative of a wavefunction out to infinity should approach zero as well. This is the same as in, say, an infinite well, where the wavefunction must be zero at the well wall. For the derivative of the wavefunction to also be continuous at the boundary, it must approach zero smoothly.
 

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