Properties of integration on Jordan Regions and stuff

SNOOTCHIEBOOCHEE
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Homework Statement




Let f : Rn ----> R.
i) Let E1 and E2 be two Jordan regions in Rn such that E1 C E2 Suppose f is integrable
on E2. Then, show that f is integrable on E1.
ii) Suppose f is continuous on Rn. Then, show that f is integrable on any Jordan region
E in Rn. Here, E is bounded.


The Attempt at a Solution



These both seem really easy to me and i can't figure it out.


For part two, is it enough to show that E is of measure zero? and how do you do that?
 
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How do you define integrable? Suppose f were NOT integrable on E1. What would that tell you about the integral on E2?

As for (ii), you are told only that E is bounded. Why in the world would you think that it has measure 0?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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