[itex]p\bar{p}[/itex] pair is a CP eigenstate?(adsbygoogle = window.adsbygoogle || []).push({});

As [itex]p[/itex] and [itex]\bar{p}[/itex] are fermions (the pair is assumed to be at S-state), the pair seems to be C's eigenstate with eigenvalue of -1.

As they have opposite intrinsic parity, the pair state seems to be P's eigenstate with eigenvalue -1. Then isn't it CP eigenstate with eigenvalue of 1?

But why the [itex]p[/itex][itex]\bar{p}[/itex] pair cannot produce [itex]K_S[/itex] or [itex]K_L[/itex] but only [itex]\bar{K}^0[/itex]?

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# A Proton anti-proton pair and CP eigenstate

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