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A Proton anti-proton pair and CP eigenstate

  1. Oct 15, 2017 #1
    [itex]p\bar{p}[/itex] pair is a CP eigenstate?

    As [itex]p[/itex] and [itex]\bar{p}[/itex] are fermions (the pair is assumed to be at S-state), the pair seems to be C's eigenstate with eigenvalue of -1.

    As they have opposite intrinsic parity, the pair state seems to be P's eigenstate with eigenvalue -1. Then isn't it CP eigenstate with eigenvalue of 1?

    But why the [itex]p[/itex][itex]\bar{p}[/itex] pair cannot produce [itex]K_S[/itex] or [itex]K_L[/itex] but only [itex]\bar{K}^0[/itex]?
    Last edited: Oct 15, 2017
  2. jcsd
  3. Oct 16, 2017 #2

    Vanadium 50

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    Not necessarily. The rest of the message assumes this, so there's no point in commenting on it.
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