bonfire09 said:
Homework Statement
Let nεZ,Prove that 1-n^2>0, then 3n-2 is an even integer.
The above is confusing. A better statement would be
Let n ##\in## Z. If 1 - n
2 > 0, then show that 3n - 2 is an even integer.
bonfire09 said:
The Attempt at a Solution
I proved it like this. I think its right but I am not able to word it correctly.
Since 1-n^2>0 therefore n=0. Then 3n-6=3(0)-6=-6. Since 0 is an integer, 3n-6 is even.
How can I learn to word this correctly because I am having some trouble with it?
Note that you have a typo in your work. You're supposed to prove that 3n -
2 is an even integer.
I would say it like this:
Since 1 - n
2 > 0 and n ##\in## Z, then n = 0.
So 3n - 2 = - 2, which is an even integer.
Therefore, for any integer n, if 1 - n
2 > 0, then 3n - 2 is an even integer.
Whovian said:
Try posting in the number theory forum, this isn't really calculus.
It should NOT be posted in the number theory section. That section and the other sections under Mathematics are not for homework and homework-type problems
Whovian said:
No, here is probably fine, although the Precalc Mathematics section would also be a good choice.