Prove CD/AB=DE/AE when A=D in Diagram

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To prove that CD/AB = DE/AE when Angle A = Angle D, it is established that triangles ABE and EDC are congruent due to the equal angles AEB and DEC, leading to the conclusion that angles ABE and DCE are also equal. This congruence implies that the triangles are similar, allowing the use of the proportion law. Consequently, the relationship CD/AB = DE/AE can be derived from the properties of similar triangles. The discussion emphasizes the importance of angle congruence in establishing triangle similarity. Overall, the proof hinges on the congruence and similarity of the triangles involved.
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How do you prove that CD/AB = DE/AE when Angle A = Angle D in the attached Diagram??

THanks
 

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Here is the image
 

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if angle A = angle D
what can u say about the triangles ABE and EDC?
what conclusion can u make?
 
Not sure I am wrong but here is my first thoughts

Angle AEB = Angle DEC

Therefore Angle ABE = Angle DCE

which means that the two triangles are congruant

This is my tought
 
u can get to say that those triangles are similar
so u can use the proportion law
and obtain the result
ok?
 

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