Prove dual space has the direct sum decomposition

jpcjr
Messages
16
Reaction score
0
I apologize for not having any attempted work, but I have no idea how to even begin tackling this proof.

Any direction would be greatly appreciated!

Mike


Homework Statement



Let V be a vector space,

Let W1, ..., Wk be subspaces of V, and,

Let Vj = W1 + ... + Wj-1 + Wj+1 + ... + Wk.

Suppose that V = W1 \oplus ... \oplus Wk.

Prove that the dual space V* has the direct-sum decomposition V* = Vo1 \oplus ... \oplus Vok.

Homework Equations



See above.

The Attempt at a Solution



Again, I apologize for not having any attempted work, but I have no idea how to even begin tackling this proof.
 
Physics news on Phys.org
What is the {}^\circ in V_j^\circ?
 
What is the " o " in Voj?

Definition.
If V is a vector space over the field F and S is a subset of V, the annihilator of S is the set So of linear functionals f on V such that f(α) = 0 for every α in S.
.
.
.
 
OK. You must prove

V^*=V_1^\circ \oplus ... \oplus V_n^\circ

What does that mean?? What is the definition of a direct sum? What is it you need to check?
 
Thank you!

By the skin of my teeth, some help from you, and the grace of God, I received the best grade I could have expected in Linear Algebra.

Thanks, again!

Joe
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top