Prove/Find Counterexample: Intro to Set Theory

mbcsantin
Messages
16
Reaction score
0

Homework Statement



Prove or find counterexamples. For any sets A, B, C in a universe U:

if A union C contained B union C then A contained B

Homework Equations



none.

The Attempt at a Solution



im just not sure if i did it right. id appreciate if you can check my work and let me know what changes i have to make. thanks

Let A be the empty set, and let B = C
Then A union C = B and
B union C = B so,
A union C contains B union C, but A does not contain B because A is the empty set and B is not.
 
Physics news on Phys.org
Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.
 
e(ho0n3 said:
Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.

alright. thank you so much!
 
e(ho0n3 said:
Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.

But what if I use the element proof for this..

Supposed that A is a subset of B.

Let x is an element of A u C.
therefore, x is an element of A and x is an element of C.
Since A is a subset of B by the definition of containment, x is an element of B.
Since x is an element of B and x is an element of C, we have x is an element of B u C. so any element of B u C is also in A u C. therefore, A u C is a subset of B u C.

Would this be right?
 
You are giving a counter example. You don't need a general proof, just any single counter example. You could just take A= {}, B= {1}, C= {1}.
 
mbcsantin said:
Let x is an element of A u C.
therefore, x is an element of A and x is an element of C.

No, that implies x is an element of A or x is an element of C.

Anyway, what you did here is irrelevant to your original question.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
7
Views
1K
Replies
1
Views
1K
Replies
13
Views
4K
Replies
3
Views
1K
Replies
1
Views
2K
Replies
5
Views
2K
Replies
2
Views
2K
Back
Top