Prove Finite Dimensional Normed Vector Space is Differentiable

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SUMMARY

The discussion focuses on proving the differentiability of the function f: U --> U, defined by f(T) = T-1, where U is the set of invertible elements in L(V), a finite dimensional normed vector space. The derivative is established as Df(T)H = -T-1HT-1. Key propositions regarding the convergence of sequences and invertibility conditions in normed vector spaces are utilized to support the proof.

PREREQUISITES
  • Understanding of finite dimensional normed vector spaces
  • Familiarity with linear operators in L(V)
  • Knowledge of differentiability in the context of functional analysis
  • Proficiency in the properties of invertible operators and their norms
NEXT STEPS
  • Study the properties of differentiable functions in Banach spaces
  • Learn about the implications of the Inverse Function Theorem in normed vector spaces
  • Explore the concept of Fréchet derivatives in functional analysis
  • Investigate the relationship between operator norms and convergence of sequences in L(V)
USEFUL FOR

Mathematicians, graduate students in functional analysis, and anyone studying the differentiability of functions in the context of normed vector spaces will benefit from this discussion.

cassiew
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Homework Statement



Let V be a finite dimensional normed vector space and let U= L(V)*, the set of invertible elements in L(V). Show, f:U-->U defined by f(T)= T-1 is differentiable at each T in U and moreover,
Df(T)H = -T-1HT-1
where Df(T)= f'(T).


Homework Equations



Apparently these propositions are supposed to help (which I've already proved and can use):

1.) Let V be a normed vector space and suppose T is an element of L(V). If ||T||<1, then the sequence Sn=sum(from j=0 to n) of Tj converges. Moreover, I-T is invertible, (Sn) converges to (I-T)-1, and ||(I-T)-1||<= 1/(1-||T||).

2.) Suppose V is a normed vector space and T, an element of L(V), is invertible. If S is an element of L(V) and ||T-S||<||T-1||-1, then S is invertible.


The Attempt at a Solution



I've already proven that the function q:V-->V where q(T)=T2 is differentiable at each T and Dq(T)H= TH+HT, and I tried to prove this one using the same technique, but it's getting me nowhere.
 
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First try differentiating f at I; your proposition 1 should help with this. Then see if you can find a way to transfer that computation to any T \in U.
 
Nevermind, I think I figured it out.
 

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