Prove H Contains in gH ≠ g-H: Counting Principles

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Homework Statement


Suppose that H is a subgroup of G such that whenever H a is not equal to H b.
Then a H not equal to b H.
Prove that g H g ^-H
Contains H.
For all g Is an element of G.[/B]

Homework Equations

The Attempt at a Solution


I tried the contrapositive position
( sorry, I'm doing this on an iPhone and I can't access latex )
 
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Are you sure you haven't a mistake in there? ##H \subseteq gHg^{-1}H## for all ##g\in G## means, ##H \trianglelefteq G## is a normal subgroup. What about ##G=Sym (3) = \{1,(12),(13),(23),(123),(132)\}## and ##H=\{1,(12)\}##?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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