What does isotropic here mean? Invariant under rotations (elements from SO(3) )?
I have the feeling you should be a bit more precise. Usually, one derives invariant tensors under specific group elements from group decomposition. You're working in three dimensional Euclidean space, so you should look at spatial rotations, which are elements of SO(3). For instance, if you denote by V the vector representation of SO(3) and by S the scalar representation, one should have
<br />
V \otimes V \otimes V = S_A + \ldots<br />
This means that the tensor product of three vectors can be decomposed in a completely antisymmetric part (which is the meaning of the subscript A) plus other stuff not important for your question. A completely antisymmetric 3-tensor in 3 dimensions has one independent component (check this!), and hence is "effectively a scalar". This shows that one has an invariant (isotropic!) tensor in three dimensions which is completely antisymmetric: the Levi-Civita 'tensor'.
Note that this is not a tensor for general transformations; one uses the fact that the determinant of an element of SO(3) is +1. Technically, it is a tensor density!