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Albert1
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A rhombus with side length 5
if diagonal BD $\geq 6$
and diagonal AC $\leq 6$
Prove : max (AC+BD)=14
if diagonal BD $\geq 6$
and diagonal AC $\leq 6$
Prove : max (AC+BD)=14
Albert said:A rhombus with side length 5
if diagonal BD $\geq 6$
and diagonal AC $\leq 6$
Prove : max (AC+BD)=14
"Max" is short for "maximum" and it refers to the largest possible value. In other words, we are looking for the highest possible value of AC + BD in this equation.
In order to prove this equation, we need to use mathematical concepts and principles such as algebra, properties of inequalities, and possibly some geometric theorems.
Sure! For example, if AC = 6 and BD = 8, then AC + BD = 14. This would be the maximum possible value for this equation.
This equation is not always true. It depends on the values of AC and BD. However, there is always a maximum value that can be reached by adjusting the values of AC and BD.
This equation may be important in science because it could be used to model or represent a real-life situation. For example, it could be used to determine the maximum amount of force that can be applied to a structure before it collapses.