Prove Symmetric Matrix with Orthogonal Matrix

arunma
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I've got a question regarding orthogonal matrices. I am given an orthogonal matrix M, and a symmetric matrix A. I need to prove that (M^-1)*A*M is also symmetric (all of the matrices are n x n). I know that for an orthogonal matrix, its inverse is equal to its transpose. Can anyone give me some hints on how to begin this proof?
 
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It seems to me that the obvious first thing to do would be to look at the transpose of (M^-1)*A*M.
 
Hurkyl said:
It seems to me that the obvious first thing to do would be to look at the transpose of (M^-1)*A*M.

Thanks for the tip. I believe the transpose of that matrix would also be (M^-1)*A*M, since (AB)^T = B^T * A^T. And if a matrix equals its own transpose, doesn't that make it symmetric?

Well, I guess that in my commentary, I've accidentally solved the problem. Thanks.
 
Don'cha hate when that happens!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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