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mahler1
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Homework Statement .
Prove or disprove that the function ##f(x)= x^2sin^2(\dfrac{\pi}{x})## if ##0<x\leq 1## and ##f(x)=0## if ##x=0## is of bounded variation. The attempt at a solution.
I've seen the graph of this function on wolfram and for me it's clearly not of bounded variation since it has too many jumps (when ##x## approaches ##0##, ##f(x)## changes its value "too quickly"). The problem is I don't know how to prove it formally.
I've tried to prove it by contradiction: Suppose ##f(x)## is of bounded variation, then there exists ##M>0 : \sum_{k=1}^n|Δf_k|\leq M## for every partition ##π=\{x_0,...,x_n\}## of ##[0,1]##.
Which is the proper partition ##π=\{x_0,...,x_n\}## of the interval ##[0,1]## such that ##\sum_{k=1}^n|Δf_k|> M##? I need help to find the appropiate partition that would lead me to a contradiction.
Prove or disprove that the function ##f(x)= x^2sin^2(\dfrac{\pi}{x})## if ##0<x\leq 1## and ##f(x)=0## if ##x=0## is of bounded variation. The attempt at a solution.
I've seen the graph of this function on wolfram and for me it's clearly not of bounded variation since it has too many jumps (when ##x## approaches ##0##, ##f(x)## changes its value "too quickly"). The problem is I don't know how to prove it formally.
I've tried to prove it by contradiction: Suppose ##f(x)## is of bounded variation, then there exists ##M>0 : \sum_{k=1}^n|Δf_k|\leq M## for every partition ##π=\{x_0,...,x_n\}## of ##[0,1]##.
Which is the proper partition ##π=\{x_0,...,x_n\}## of the interval ##[0,1]## such that ##\sum_{k=1}^n|Δf_k|> M##? I need help to find the appropiate partition that would lead me to a contradiction.
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