Prove that a zero-one matrix can only have 1's after 5th power

  • Context: Graduate 
  • Thread starter Thread starter leo255
  • Start date Start date
  • Tags Tags
    Matrix Power
Click For Summary
SUMMARY

A zero-one matrix, specifically the matrix A[1] defined as [[0, 0, 1], [1, 0, 0], [1, 1, 0]], will yield a matrix of all 1's after raising it to the 5th boolean power, resulting in A[5] as [[1, 1, 1], [1, 1, 1], [1, 1, 1]]. This property holds true for any power greater than or equal to 5, as the boolean product of rows ensures that each column will contain at least one "1". The proof can be established through direct calculation for A[1] and formal induction for powers 6 and above.

PREREQUISITES
  • Understanding of boolean matrix multiplication
  • Familiarity with matrix powers and their properties
  • Knowledge of mathematical induction
  • Basic concepts of linear algebra
NEXT STEPS
  • Study boolean matrix multiplication techniques
  • Learn about matrix exponentiation and its applications
  • Explore mathematical induction proofs in linear algebra
  • Investigate properties of zero-one matrices in graph theory
USEFUL FOR

Mathematicians, computer scientists, and students studying linear algebra or graph theory, particularly those interested in matrix properties and proofs.

leo255
Messages
57
Reaction score
2
Hello,

I couldn't give the full explanation in the title - I am talking about a particular matrix. Given the matrix:

A[1] =

0 0 1
1 0 0
1 1 0

A[5] =

1 1 1
1 1 1
1 1 1

Once it gets to the 5th boolean power, it becomes all 1's, and any power greater than or equal to 5 will always produce a matrix of all 1's. I know that this will always be true because A[5], A[6], A[N] will always have only 1's, and that since A[1] has at least one "1" in each column, that will always be enough to produce a one in each column, when taking the boolean product of each row of A. I understand this, but am not sure how to put it into a proof. Would appreciate any tips.
 
Physics news on Phys.org
A proof for this specific A[1]? Just calculate it. For 6+, you can show formally via induction that it doesn't change any more.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K