Prove that all convergent sequences are bounded

converting1
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was looking at a proof of this here: http://gyazo.com/8e35dc1a651cec5948db1ab14df491f8

I have two questions,

why do you set K = max of all the terms of the sequence plus the 1 + |A| term? Why do you need the absolute value of all the terms? i.e. why |a_1| instead of |a_1|?
 
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converting1 said:
was looking at a proof of this here: http://gyazo.com/8e35dc1a651cec5948db1ab14df491f8

I have two questions,

why do you set K = max of all the terms of the sequence plus the 1 + |A| term? Why do you need the absolute value of all the terms? i.e. why |a_1| instead of |a_1|?

Because ##|x_n|< L+1## only holds for ##n > N##. If some of the first ##N## terms are larger than all the rest, use the biggest one of them for the bound.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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