Prove that nCk is a natural number

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Homework Statement



Prove that \binom{n}{k} is a natural number by showing that \binom{n}{k} is the number of sets of exactly k integers each chosen from 1, ..., n.

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The Attempt at a Solution



I posted a similar question before (https://www.physicsforums.com/showthread.php?t=339363) which asked for a proof by induction. This question is a bit different, and I'm not entirely sure how to get started. I'd appreciate some hints. Thanks.
 
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Here's your hint. How many different sequences (ordered!) of integers can you pick from the set {1,...,n}? Count sequences. Mull over that for a bit.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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