Prove that there is no positive real

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Homework Statement


Prove that there exists no smallest positive real number.

The Attempt at a Solution


Lets assume for contradiction that x is the smallest positive real.
Now we will look at the midpoint between 0 and x which is x/2, well x/2 is positive and smaller than x so this is a contradiction, so there is no smallest positive real.
 
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Looks fine to me. If you want to be pedantic, you may want to prove explicitly that ##x/2## is positive and strictly less than ##x##.
 
Depending on how much rigor you need to put in, you might want to prove ##0<\frac{x}{2}<x##. I know it's trivial, so perhaps it's not needed.
 
ok thanks, it almost seemed to easy just wanted to make sure it worked.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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