Prove that Wm is a subspace of R2?

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SUMMARY

The subset Wm = {(mx, x) | x ∈ R} is proven to be a subspace of R² by demonstrating that it contains the zero vector, is closed under addition, and is closed under scalar multiplication. The zero vector (0, 0) is included in Wm when x = 0. For closure under addition, if u = (mx₁, x₁) and v = (mx₂, x₂) are in Wm, then u + v = (m(x₁ + x₂), x₁ + x₂) is also in Wm. For scalar multiplication, if u = (mx, x) and k ∈ R, then ku = (k(mx), kx) = (m(kx), kx), confirming closure. The union of all Wm is not a subspace of R² as it fails to meet the criteria for closure.

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  • Understanding of vector spaces and subspace criteria
  • Familiarity with R² and its geometric representation
  • Knowledge of scalar multiplication and vector addition
  • Ability to manipulate algebraic expressions involving vectors
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I need help with this problem that I don't know how to solve.

Homework Statement



For each positive integer m, it's defined a subset of R2 as Wm={(mx,x)|x in R}
(a) Prove that each Wm is a subspace of R2.
(b) ¿Is the union of all Wm a subspace of R2?. Prove it.

Homework Equations



None.

The Attempt at a Solution



Trying to prove (a)
To prove Wm is a subspace we know we have to show that
(1) 0 vector is in Wm
(2) Given u,v in Wm; then u+v is an element of Wm
(3) Given u in Wm, k in R, then k*u is an element of Wm

I don't know how to prove (2)
I have a problem proving (3), if we choose k in R, if k is negative, then km is negative and we'd have Wm=((km)x,x) with km negative, then ku for some u in Wm is not an element of Wm.

Trying to prove (b)
I have no idea at all.

Thanks for your time.
 
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To prove (2), you need to write out what u and v "look like" since they are elements of W_m. For (3), I think you're making a mistake in your multiplication. Normally the definition is
<br /> c(x,y) = (cx, cy) \; .<br />

For (b), try to think of what W_m represents geometrically. If you're having trouble with it, you can always try drawing an example for a specific value of m.
 
spamiam said:
To prove (2), you need to write out what u and v "look like" since they are elements of W_m. For (3), I think you're making a mistake in your multiplication. Normally the definition is
<br /> c(x,y) = (cx, cy) \; .<br />

For (b), try to think of what W_m represents geometrically. If you're having trouble with it, you can always try drawing an example for a specific value of m.


Thanks, proving (2) giving u is an element of Wm then u=(mx,x) x in R, now I know how to prove Wm is a subspace. Proving 3, you're right I forgot about the second coordinate.
 

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