Prove the Following is True About the Complex Function f(z) = e^1/z

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Discussion Overview

The discussion revolves around the complex function \( f(z) = e^{1/z} \) and the challenge of proving that for any non-zero complex number \( w_0 \) and any \( \delta > 0 \), there exists a complex number \( z_0 \) such that \( 0 < |z_0| < \delta \) and \( f(z_0) = w_0 \). The scope includes mathematical reasoning and exploration of complex analysis concepts.

Discussion Character

  • Mathematical reasoning
  • Exploratory

Main Points Raised

  • Some participants suggest starting by substituting \( z = 1/u \) and finding a complex number \( u \) such that \( |u| > 1/\delta \) and \( e^u = w_0 \).
  • There is a proposal to solve separately for the absolute value and argument of \( w_0 \), questioning the loci of points \( u \) for which \( e^u \) is constant.
  • One participant asks if letting \( u = \frac{2}{\delta} + \arg(w_0)i \) is a valid approach.
  • A later reply clarifies that if \( u = x + yi \), then \( e^u = e^x \cdot e^{yi} \), leading to conditions on \( x \) and \( y \) to satisfy \( e^u = w_0 \), including the need for \( n \) to be an integer.
  • It is noted that by choosing \( n \) large enough, one can ensure \( |u| > 1/\delta \).

Areas of Agreement / Disagreement

Participants generally explore the problem collaboratively, but no consensus is reached on a definitive solution or approach. Multiple viewpoints and methods are presented without resolution.

Contextual Notes

Participants express uncertainty regarding the correct formulation of \( u \) and the implications of the argument's periodicity in the complex plane. The discussion does not resolve the mathematical steps required to prove the initial claim.

Deanmark
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Consider the function $f(z) = e^{1/z}$,
Show that for any complex number ${w}_{0} \ne 0$ and any δ > 0, there exists ${z}_{0} ∈ C$
such that $ 0 < |{z}_{0}| < δ$ and $f({z}_{0}) = {w}_{0}$

I really don't know where to begin on this.
 
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Deanmark said:
Consider the function $f(z) = e^{1/z}$,
Show that for any complex number ${w}_{0} \ne 0$ and any δ > 0, there exists ${z}_{0} ∈ C$
such that $ 0 < |{z}_{0}| < δ$ and $f({z}_{0}) = {w}_{0}$

I really don't know where to begin on this.
Hi,

You could start by writing $z=1/u$; given $w_0$, you must now find a complex number $u$ with $|u|>1/\delta$ and $e^u=w_0$, which means that $|u|$ can be arbitrarily large.

You should try to solve separately for the absolute value and the argument of $w_0$. What is the locus of the points $u$ such that $e^u$ is constant in the complex plane? What is the locus of the points with $\arg e^u$ constant?

Can you prove that there exist arbitrarily large $u$ that satisfy both conditions?
 
castor28 said:
Hi,

You could start by writing $z=1/u$; given $w_0$, you must now find a complex number $u$ with $|u|>1/\delta$ and $e^u=w_0$, which means that $|u|$ can be arbitrarily large.

You should try to solve separately for the absolute value and the argument of $w_0$. What is the locus of the points $u$ such that $e^u$ is constant in the complex plane? What is the locus of the points with $\arg e^u$ constant?

Can you prove that there exist arbitrarily large $u$ that satisfy both conditions?

Should we let the complex number u = $\frac{2}{\delta}$ + arg(${w}_{0})$i ?
 
Deanmark said:
Should we let the complex number u = $\frac{2}{\delta}$ + arg(${w}_{0})$i ?
Hi Deanmark,

You are almost there, but not quite. If $u=x+yi$, then $e^u=e^x\cdot e^{yi}$, and we have $|e^u| = |e^x|$ and $\arg e^u = y$ for any integer $n$.

To have $e^u=w_0$, you must have:

$$\begin{align*}
x &= \ln w_0\\
y &= \arg w_0 + 2n\pi
\end{align*}$$

where $n$ is any integer (because the argument is defined up to a multiple of $2\pi$, or, to put it otherwise, because $e^{2\pi i}=1$).

The first equation describes a vertical line. By taking $n$ large enough (for example, $n>\dfrac{1}{2\pi\delta})$, you can ensure that $|u|>1/\delta$.
 

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