Prove there are infinitely many primes using Mersenne Primes

Kitty Kat
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Homework Statement


Prove that there are infinitely many primes using Mersenne Primes, or show that it cannot be proven with Mersenne Primes.

Homework Equations


A Mersenne prime has the form: M = 2k - 1

The Attempt at a Solution


Lemma: If k is a prime, then M = 2k - 1 is a prime.
Proof of Lemma: Assume that k is composite, then 2k - 1 must also be composite.
k = a * b
2ab - 1 is then divisible by both (2a - 1) and (2b - 1)
Therefore k must be a prime.

Proof for problem

Assume there are finitely many primes, p1, ... , pr, and let pr be the last prime.

Then by Lemma 1, 2pr - 1 is a Mersenne prime, which is certainly larger than pr, therefore there are infinitely many primes.
After writing all this out, I realized that the lemma is most certainly false, so I guess there isn't a way to prove infinitely many primes with Mersenne Primes, since the number of Mersenne Primes themselves are an open question.
 
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You appear to think you have proved that if ##k## is prime, then ##2^k -1## is prime. This is false. E.g ##k = 11##

You have proved the converse: If ##2^k -1## is prime, then ##k## is prime.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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