Prove this (periodic function)

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Homework Help Overview

The discussion revolves around proving a property of a periodic continuous function with a specified period. The original poster seeks to demonstrate that there exists an x such that f(x + π) = f(x).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the Intermediate Value Theorem by defining a function g(x) = f(x + π) - f(x) and considers the interval [π, π + 1]. Some participants question the choice of interval and suggest that the function must attain maximum and minimum values.

Discussion Status

Participants are exploring different approaches to the problem, with some providing guidance on the use of the Intermediate Value Theorem and the need for appropriate interval selection. There is no explicit consensus, but the discussion is progressing with constructive feedback.

Contextual Notes

There is an emphasis on the properties of periodic functions and the conditions necessary for applying the Intermediate Value Theorem effectively. The original poster's approach is noted to have potential gaps that are being addressed by other participants.

sayan2009
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please prove this (periodic function)

Homework Statement



if f is periodic continuous function with period 1 then show there exists x such that f(x+pi)=f(x)

Homework Equations





The Attempt at a Solution


i am trying in this way,considering interval [pi,pi+1],and taking g(x)=f(x+pi)-f(x).and trying to use intermediate value theorem...but stuck on that
 
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Sine and cosine are cyclic functions...
 


r u tryin to use Fourier expansion
 


sayan2009, I like your function g(x), and I like that you are using the IVT, but your interval doesn't work. You need numbers a and b where g(a) will be positive and g(b) will be negative (or vice versa). I bet you will have good luck if you first consider the fact that f must attain its maximum and minimum values.
 

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