Proving a function is well defined and continuous

mick25
Messages
13
Reaction score
0

Homework Statement


Let f_{n}(x)=\frac{-x^2+2x-2x/n+n-1+2/n-1/n^2}{(n ln(n))^2}

Prove f(x) = \sum^{\infty}_{n=1} f_{n}(x) is well defined and continuous on the interval [0,1].

Homework Equations



In a complete normed space, if \sum x_{k}converges absolutely, then it converges.

The Attempt at a Solution



Working in a complete normed space (C[0,1], || . ||_{∞}),

consider the real series \sum^{∞}_{n=1}||f_{n}||_{∞}=\sum^{∞}_{n=1} sup <f_{n}(x) : x\in[0,1]>

It just remains to show that \sum^{∞}_{n=1}|f_{n}| converges, but I can't seem to figure out how. Could anyone help me out here?
 
Last edited:
Physics news on Phys.org
some ideas i haven't tried them yet though... how about first separating n into some manageable pieces...

first evaluate the convergence of the terms only dependent on n, then consider the terms with an x and have a think about what x value will maximize that sum.

then if it's tough to pull it together you may want to consider some properties of the norm.

then I think you may need more for the continuous part and move to the epsilon deltas
 
Rather than dealing with all the terms separately, I've been trying to just apply a simple comparison test (followed by an integral test) to prove its convergence, but I could only come up with divergent cases.

I'm starting to think if there is an error with this question; does this series converge if it starts at n=1?
 
yeah as 1/ln(1)^2 is undefined
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top