Proving a metric is continuous

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Homework Statement



So, given a metric d : X x X --> R, prove that d is continuous.

The Attempt at a Solution



Let (x, y) be a point in X x X, V = <a, b> a neighborhood of d(x, y). One needs to find a neighborhood of U of (x, y) such that d(U) is contained in V. U is of the form U1 x U2, where U1 is a neighborhood of x, and U2 a neighborhood of y. I claim that every union U of two open balls B1(x, r1) and B2(y, r2), where 2(r1 + r2) = b - a, must satisfy d(U) \subseteq <a, b>.

The diameter of B1 is 2r1, and the diameter of B2 is 2r2. The diameter of their union is b = a + 2r1 + 2r2, where a is the distance between B1 and B2.

Does this work?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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