Bashyboy
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Homework Statement
suppose f~:~A \rightarrow B be a surjective map of sets. Prove that the relation a Rb \iff f(a)=f(b) is a equivalence relation whose equivalence classes are the fibers of f.
Homework Equations
The Attempt at a Solution
I was able to easily prove that the relation satisfied the reflexive and symmetric part, but there are a few details of the transitive case that I am uncertain of. Here is some of my work:
Suppose that (a,b) \in R and (b,c) \in R, meaning that the function f maps the elements a and b to the same element in the codomain, call it \alpha, and the function maps b and c to the same element; that is, f(a) = f(b) and f(b) = f(c). Does this immediately imply that f(a) = f(c), or do I have to do some further reasoning, such as reiterating that f is indeed a function, which means that f can only associate one element in its codomain to each element in its domain, suggesting that f(b) = \alpha = \beta?
For instance, suppose in the problem that f was not specified as a function. Then if f was f(x) = \pm \sqrt(x), then it wouldn't be transitive, right?