Proving a transformation is linear

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Homework Statement


0%5Cbegin%7Bbmatrix%7D%202x_1%20-%203x_2%5C%5C%202x_2%5C%5C%204x_1%20+%203%20%5Cend%7Bbmatrix%7D.gif

If T is linear, show that it is linear by finding a standard matrix A for T so that:
gif.gif

Also show that this equation holds for the matrix you have found. If T is not linear, prove that T is not linear by showing that it does not fit the definition of a linear transformation

Homework Equations


Definition of a linear transformation:
T(\vec{u}+\vec{v}) = T(\vec{u})+T(\vec{v})
T(c\vec{u}) = cT(\vec{u})

The Attempt at a Solution


First I let $$ \vec{e}_{1} =
\begin{bmatrix}
1\\
0
\\0

\end{bmatrix} $$
$$ \vec{e}_{2} =
\begin{bmatrix}
0\\
1
\\0

\end{bmatrix}$$
$$ \vec{e}_{3} =
\begin{bmatrix}
0\\
0
\\1

\end{bmatrix}$$
However, when I go to separate
$$
\vec{b} = \begin{bmatrix}
2x_1 - 3x_2\\
2x_2\\
4x_1 + 3
\end{bmatrix}$$ I am not sure how to handle the constant, i.e, I am not sure how to rewrite as A\vec{x}. I think once I figure that out I should be able to do the rest of problem
 
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It is not linear ... Just find a counter example to the definitions of what a linear transformation is.
 
(Edit : deleted, duplicate response)
 
Last edited:
Orodruin said:
It is not linear ... Just find a counter example to the definitions of what a linear transformation is.
Ok, I didn't realize that was all I needed to do. I have attached a picture of my work because it would be kind of long to write out in latex:
hsPShzu.jpg
 
You could simplify that a lot. If T is linear, then T(0)=0, since T(0x)=0T(x). Is it for your given T?
 
Dick said:
You could simplify that a lot. If T is linear, then T(0)=0, since T(0x)=0T(x). Is it for your given T?
wow I hadn't thought of that, sort of makes the problem trivial lol...anyway thanks for the help :)
 
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