Proving Bounds for a Riemann Sum: Part II

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Homework Help Overview

The discussion revolves around a Riemann sum problem involving the function f(x) = x^(3/2) over the interval [0, 100]. Participants are tasked with proving bounds for a finite sum S_n, specifically S_99 and S_100, using upper and lower Riemann sums.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of Riemann sums to establish bounds for S_99 and S_100. There is confusion regarding the definition of J and the interpretation of the inequalities involving S_99 and S_100. Some participants question the clarity of the problem statement and the relationship between the sums and the integral.

Discussion Status

The discussion is ongoing, with some participants clarifying terms and attempting to establish the bounds for J. There is acknowledgment of previously calculated bounds, but uncertainty remains regarding the next steps and the specific requirements of the problem.

Contextual Notes

Participants note that the bounds for S_99 are established as 40000 < J < 41000, but there is uncertainty about how to derive bounds for S_100 that meet the specified criteria of being no more than 1000 units apart.

ronho1234
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this is a riemann sum question and i need help with part 2

let Sn denote the finite sum 1+2^ 3/2 +...+n^ 3/2

i) use suitable upper and lower riemann sums for the function f(x)=x^3/2 on the interval [0,100] to prove that S99<J<100

ummm i did this and found 40000<J<41000

II) hence, or otherwise, find integer lower and upper bounds, no more than 1000 units apart, for S100

ummm i don't understand what the question is asking me...
 
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Do you mean S99< J< S100 rather than S99< J< 100? And what is 'J'? You don't seem to have defined it anywhere.
 
yes i meant S100 and J is from the first part
Calculate J= the integral from 0-100 x^3/2dx which i found to be 40000 i think which leads onto the next two questions
 
Well, from your description, it seems you already did #2 , by finding a lower

bound of 40000 and an upper bound of 41000, since their difference satisfies

the condition.
 

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