Proving Closure of X/Y in Normed Spaces

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Hi there,

Could you please help me in how to prove the following :

If Y is a closed linear subspace of a normed space X, then

if X is complete ==> X/Y is complete.

Cheers,
W.
 
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Yes I can. But I won't unless you put some work into it.
 
I have an idea but I'm not sure if it is right or wrong :

Let [x_n] be a Cauchy sequence in X/Y where [x_n]=\{x_n + y | y \in Y\} that means the norm of [x_n] , [x_m] in this sequence is less than \epsilon for each m, n > N

so we want to use completeness of X, but how?

If [x_n] is a Cauchy sequence in X/Y ,then does that mean x_n is a Cauchy sequence in X ?

If so, then suppose x_n is a Cauchy sequence in X converges to x \in X, then [x_n]converges to [x] \in X\Y?

I am confused :s I think there is some thing missing :\
 
Could you also state which norm you put on X/Y?

wii said:
If [x_n] is a Cauchy sequence in X/Y ,then does that mean x_n is a Cauchy sequence in X ?

This is not true. However, you may find representatives of [x_n] that do form a Cauchy sequence. I mean: it is possible to find y_n\in [x_n], such that (y_n)_n does form a Cauchy sequence.
But it is in general not true that (x_n)_n is a Cauchy sequence...
 
|| x+Y|| = \inf _{y\in Y} ||x+y||

where ||x+y|| is the norm that defines on X.

I've already proved that ||x+Y|| defines a norm on X/Y.

Thanx in advance.
 
Given a Cauchy sequence ([x_n])_n in the quotient X/Y, find a subsequence ([x']_n)_n such that ||[x']_n-[x']_m||<2^{-n} for all n. From this, construct a Cauchy sequence in X.
 
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