Proving Constant Acceleration's Impact on Average Velocity

AI Thread Summary
To prove that the average velocity equals (vf + vi)/2 under constant acceleration, one can utilize the relationship between initial velocity (vi), final velocity (vf), and time. A diagram illustrating the velocities shows that the average velocity calculated as (20 + 20)/2 equals 20 km/h, supporting the claim. Additionally, when acceleration is constant, the velocity-time graph is linear, confirming that the average velocity is indeed the midpoint of vi and vf. Calculus can also be employed to derive the average velocity from the velocity function over time. This demonstrates that the average velocity formula holds true for constant acceleration scenarios.
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Homework Statement



Prove that if the acceleration is constant, the average velocity=vf+vi/2

Homework Equations


average velocity=xf-xi/change in t
xf=xi+vit+1/2at^2
vf^2=vi^2+2a(xf-xi)



The Attempt at a Solution



I started out by drawing a diagram:

_ _ _ _ _ _ _ _ _
Vi v vf
20km/h 20km/h

20+20/2=20

Do you think this proves it or is there another way of doing it?

Thank you in advance
 
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Could someone please help me on this?

Thank you very much
 
Can you use calculus or not?
 
vf = vi + at
Now if a=constant, the graph of velocity plotted against time is a straight line, yes? (From the equation above)
Now it is obvious that the average velocity between vf and vi must be (vf + vi)/2 from the graph.
Otherwise you can use calculus to find the time average of the velocity function.
 
Thank you very much

Regards
 
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