Proving Continuity and Linearity of a Function

ILikePizza
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Homework Statement


Given that f(x + y) = f(x) + f(y), prove that
(a) if this function is continuous at some point p, then it is continuous everywhere
(b) this function is linear if f(1) is continuous.


Homework Equations


definition of continuity


The Attempt at a Solution


(a) I think that contradcition(sp?) would work nicely here. But I'm not sure exactly how it would work. I mean, there exists a point q such that there exists a x > 0 such that for all d > 0, ... what would go in the "..."? |f(d) - f(q)| < x?

Beyond that, where do I go from there . any ideas? Is contradiction the right way to go?

(b) The only way i can think of making this work is showing if f(xc) =c f(x), we win. But again, how would you show this?

thanks in advance!
 
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Not sure for part a off the top of my head, but assuming it's solved...

For part b, start by proving it for c a natural number, then extend it to all rational numbers without using the continuity condition. Use continuity (f(1) is continuous hence by part (a) all of f is) to extend f(xc)=cf(x) for c an irrational number
 
If f is continuous at x= p, then lim_{x\rightarrow p}f(x)= f(p). Let h= x- p. Then as x goes to p, h goes to 0 and f(x)= f(p+ h)= f(p)+ f(h).
lim_{x\rightarrow} f(x)= \lim_{h\rightarrow 0}(f(p)+ f(h))= f(p)+ \lim_{h rightarrow 0} f(h)= f(p).

What does that tell you about \lim_{h\rightarrow 0} f(h).

Now for any q, look at \lim_{x\rightarrow q} f(x) by letting h= x- q.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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