Proving Continuity of Derivatives for a Multivariable Function

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Homework Statement



Suppose that the function f: R^n --> R is continuously differentiable. Let x be a point in R^n. For p a nonzero point in R^n and alpha a nonzero real number, show that
(df/d(alphap))(x)=alpha(df/d(p))(x)

Homework Equations



A function f: I --> R, defined on an open interval, is called continuously differentiable provided that it is differentiable and its derivative is continuous.

The Attempt at a Solution



Unfortunately, I do not have one. Which is why I am in dire need of help. I don't know where to begin. By the way, sorry for the horrible formatting, I am new to the forums.

Edit: Okay, I might have an attempt at a solution.
(df/d(alphap))(x)=<gradientf(x),alphap>=alpha<gradientf(x),p>=alpha(df/dp)(x)
 
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If df/d(p) means the directional derivative of f in the direction p, I think that looks ok.
 
Oh, sorry. Yeah. I was talking about the directional derivative. I don't know how to write the actual notation for directional derivatives on here. And thank you for your help!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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