Proving convergence of factorial w/o Ratio Test

mvpshaq32
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Homework Statement


Determine whether 1/n! diverges or converges.
So far, we have only learned the comparison tests, p-series, geometric series, divergence test, and integral test, so I can only use these tests to prove it.


Homework Equations



N/a

The Attempt at a Solution



I thought about using limit comparison with my b_n=1/n^n, but I can't determine if that converges or not, so I don't know what to do.
 
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Why did you choose b_n = 1/n^n? Why not a simpler series that you know converges or diverges?
 
The Comparison Test is your friend
 
It should be clear that for n> 3, n^2> n!.
 
HallsofIvy said:
It should be clear that for n> 3, n^2> n!.

I think you meant 2^n < n! ? Easy typo to make.

Oops, it's 2^(n-1) < n!
 
It's monotonic, so if you show that it is bounded, you're in business. Now by the comparison test, we have n!>n^2 for sufficiently large n, so take reciprocals and go from there.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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