Proving Divergence of (tn + sn)

  • Thread starter Thread starter dmac1215
  • Start date Start date
  • Tags Tags
    Divergence
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
dmac1215
Messages
1
Reaction score
0
I have a super round about way to prove this, but I'm having trouble finding a succinct proof

Let (tn) be diverge and (sn) converge. Show (tn+sn) diverges

The way I was doing involved considering that tn was unbounded, then showing it (sn+tn) is divergent.

Then I had to consider that tn is bounded and oscillatory, consider convergent subsequences, and show (sn+tn) had no unique limit, and therefore diverges. This part of the proof seemed less clear and I'm not sure if I can assert that because I have convergent subsequences of (tn) with multiple limits that (sn+tn) also has multiple limits.

I figure there has got to be some simple contradiction proof involving some triangle inequality trick that I'm just missing.

Thanks
 
Physics news on Phys.org