Proving dN/ds=−κT+τB: A Differential Geometry Homework Solution

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Homework Statement



Currently revising for a differential geometry exam. The question I am working on is one of those types where the next part of the question follows from the last. I've gotten to the point where I have proven T⋅dNds=−κ,

Homework Equations



The next part is where I got stuck, which is to prove dN/ds=−κT+τB. I looked at the mark scheme

The Attempt at a Solution


it said "Follows from previous item, and B=T×N". I simply don't see how it follows, though.
 
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Murtuza Tipu said:

Homework Statement



Currently revising for a differential geometry exam. The question I am working on is one of those types where the next part of the question follows from the last. I've gotten to the point where I have proven T⋅dNds=−κ,

Homework Equations



The next part is where I got stuck, which is to prove dN/ds=−κT+τB. I looked at the mark scheme

The Attempt at a Solution


it said "Follows from previous item, and B=T×N". I simply don't see how it follows, though.

You know that \frac{d\mathbf{N}}{ds} must be orthogonal to \mathbf{N}. Hence \frac{d\mathbf{N}}{ds} = C\mathbf{T} + D\mathbf{B} for some C(s) and D(s). You have shown that C = -\kappa. How do you think you should go about finding D?
 
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