Proving Eigenstate Energy: Multiply ψ(x) by Hamiltonian Operator for e-ikx

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Discussion Overview

The discussion revolves around proving that the function e-ikx is an eigenstate of the energy operator (Hamiltonian) in quantum mechanics. Participants explore the relationship between the Hamiltonian operator and the wave function, as well as the implications of the eigenvalue equation in the context of Schrödinger's equation.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant suggests starting the proof by multiplying the Hamiltonian operator by ψ(x).
  • Another participant notes that the Hamiltonian usually goes on the other side of ψ and questions the understanding of Schrödinger's equation.
  • A different participant proposes that to prove the eigenstate, they could express Hψ(x) = hψ(x) and break H down into smaller parts.
  • It is mentioned that the Hamiltonian operator for a free particle is given by the differential operator -ħ²/2m Δ.
  • One participant indicates that the plane wave function can be shown to be a generalized eigenfunction of the Hamiltonian and suggests checking the eigenvalue equation.
  • Another participant raises a concern about whether the plane wave function can represent a state of the particle in quantum theory, concluding that it cannot.
  • There is a reference to the time-independent Schrödinger equation and its relation to stationary solutions.
  • A participant expresses frustration with the symbolic nature of quantum mechanics and its application, particularly from an engineering perspective.

Areas of Agreement / Disagreement

Participants express varying degrees of understanding and approaches to the problem, with some clarifying concepts while others raise questions. There is no clear consensus on the best method to prove that e-ikx is an eigenstate energy.

Contextual Notes

Some participants reference specific mathematical forms and relationships, but the discussion does not resolve the implications of these forms or the conditions under which they apply.

TheNE
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show that e-ikx is an eigenstate energy.

Do I start by multiplying the hamiltonian operator by ψ(x)?

So far I have ψ(x)(1/2m)(-i[STRIKE]h[/STRIKE]d/dx)2=e-ikx
 
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The Hamiltonian usually goes on the other side of [itex]\psi[/itex]
Do you know schrodingers equation?
 
-[STRIKE]h[/STRIKE]2/2m d2/dx2 eikx-iωt right?

To prove the eigenstate, I could just have Hψ(x)=hψ(x) and break H down into it's smaller parts, right? I thought I took good enough notes on eigenvalues... Tyvm!
 
Where H is the Hamiltonian operator
 
There's a right hand side to schrodingers equation too :P
 
It has not so much to do with the Schrödinger equation, but with the eigenvalue problem for the Hamiltonian [itex]\hat{H}[/itex]. In position space the Hamilton operator for a free particle is given by the differential operator
[tex]\hat{H}=-\frac{\hbar^2}{2m} \Delta.[/tex]
It's indeed easy to schow that the plane wave
[tex]u_{\vec{k}}(\vec{x})=N \exp(\mathrm{i} \vec{k} \cdot \vec{x})[/tex]
is a generalized eigenfunction of [itex]\hat{H}[/itex] (with [itex]N[/itex] an arbitrary constant). Just take the derivatives and check that it fulfills the eigenvalue equation
[tex]\hat{H} u_{\vec{k}}(\vec{x})=E_{\vec{k}} u_{\vec{k}}(\vec{x}).[/tex]
You'll easily find the energy eigenvalue.

Also think about, whether this function can ever represent a state of the particle in the sense of quantum theory. To help a bit: The answer is a clear no!

Sometimes the eigenvalue equation for the Hamilton operator is called "the time-independent Schrödinger equation". Indeed, the relation with the Schrödinger equation,
[tex]\mathrm{i} \hbar \partial_t \psi(t,\vec{x})=\hat{H} \psi(t,\vec{x}),[/tex]
is that the function
[itex]\psi_{\vec{k}}(t,\vec{x})=u_{\vec{k}}(\vec{x}) \exp \left (-\mathrm{i} \frac{t E_{\vec{k}}}{\hbar} \right)[/itex]
is a solution. The eigenfunctions of the Hamilton operator represent the "stationary solutions", because it is constant in time up to the phase factor [itex]\exp(-\mathrm{i} t E_{\vec{k}}/\hbar)[/itex].
 
Thanks guys, I got help from my classmates and they walked me through the solution. I wish quantum mechanics (or what I've been exposed to it thus far in my Modern Physics course) was less "symbolic" and easier to apply. As an engineering student, I always seek ways to apply my knowledge, and this really messes with me haha.
 

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