Proving Eigenstate Energy: Multiply ψ(x) by Hamiltonian Operator for e-ikx

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TheNE
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show that e-ikx is an eigenstate energy.

Do I start by multiplying the hamiltonian operator by ψ(x)?

So far I have ψ(x)(1/2m)(-i[STRIKE]h[/STRIKE]d/dx)2=e-ikx
 
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The Hamiltonian usually goes on the other side of [itex]\psi[/itex]
Do you know schrodingers equation?
 
-[STRIKE]h[/STRIKE]2/2m d2/dx2 eikx-iωt right?

To prove the eigenstate, I could just have Hψ(x)=hψ(x) and break H down into it's smaller parts, right? I thought I took good enough notes on eigenvalues... Tyvm!
 
Where H is the Hamiltonian operator
 
There's a right hand side to schrodingers equation too :P
 
It has not so much to do with the Schrödinger equation, but with the eigenvalue problem for the Hamiltonian [itex]\hat{H}[/itex]. In position space the Hamilton operator for a free particle is given by the differential operator
[tex]\hat{H}=-\frac{\hbar^2}{2m} \Delta.[/tex]
It's indeed easy to schow that the plane wave
[tex]u_{\vec{k}}(\vec{x})=N \exp(\mathrm{i} \vec{k} \cdot \vec{x})[/tex]
is a generalized eigenfunction of [itex]\hat{H}[/itex] (with [itex]N[/itex] an arbitrary constant). Just take the derivatives and check that it fulfills the eigenvalue equation
[tex]\hat{H} u_{\vec{k}}(\vec{x})=E_{\vec{k}} u_{\vec{k}}(\vec{x}).[/tex]
You'll easily find the energy eigenvalue.

Also think about, whether this function can ever represent a state of the particle in the sense of quantum theory. To help a bit: The answer is a clear no!

Sometimes the eigenvalue equation for the Hamilton operator is called "the time-independent Schrödinger equation". Indeed, the relation with the Schrödinger equation,
[tex]\mathrm{i} \hbar \partial_t \psi(t,\vec{x})=\hat{H} \psi(t,\vec{x}),[/tex]
is that the function
[itex]\psi_{\vec{k}}(t,\vec{x})=u_{\vec{k}}(\vec{x}) \exp \left (-\mathrm{i} \frac{t E_{\vec{k}}}{\hbar} \right)[/itex]
is a solution. The eigenfunctions of the Hamilton operator represent the "stationary solutions", because it is constant in time up to the phase factor [itex]\exp(-\mathrm{i} t E_{\vec{k}}/\hbar)[/itex].
 
Thanks guys, I got help from my classmates and they walked me through the solution. I wish quantum mechanics (or what I've been exposed to it thus far in my Modern Physics course) was less "symbolic" and easier to apply. As an engineering student, I always seek ways to apply my knowledge, and this really messes with me haha.