Proving Existence of Fixed Points in Continuous Sets

angelpsymon
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Homework Statement


Suppose f:[a,b] \rightarrow [a,b] is continuous. Prove that there is at least one fixed point in [a,b] - that is, x such that f(x) = x.


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The Attempt at a Solution


I was going to try something with the IVT, but then I realized I wasn't sure what they meant by a fixed point much less how to solve this problem. Any help would be appretiated.
 
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Hi Angelpsymon,

It says what a fixed point is in the problem statement: "x such that f(x) = x." You are absolutely correct in thinking to apply the intermediate value theorem. Hint: since f maps into [a,b], we must have that f(a)\geq a and f(b)\leq b.
 
As Unco suggested, maybe without spelling it out completely, apply the IVT to f(x)-x.
 
Dick said:
As Unco suggested, maybe without spelling it out completely
Apologies, Dick, I certainly didn't mean to do so.
 
You don't HAVE to spell it out completely. Hints are enough. I apologize if I spoiled your hint and made it too obvious. I was just saying how to apply the IVT.
 
Alright, I think that I got it now. Thanks a lot guys.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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