Proving Inequality: a/b < (a+1)/(b+1) for b > a | Solution and Attempt

  • Thread starter Thread starter John H
  • Start date Start date
  • Tags Tags
    Inequality
AI Thread Summary
The discussion centers on proving the inequality a/b < (a+1)/(b+1) under the condition that b is a positive number and a < b. Participants share their attempts at solving the problem, with one expressing frustration over previous methods that did not yield success. Suggestions include clearing fractions by multiplying both sides by the common denominator and adding ab to both sides of the inequality. The conversation highlights the importance of careful manipulation of inequalities and common mistakes made in the process. Overall, the thread emphasizes collaborative problem-solving in mathematical proofs.
John H
Messages
36
Reaction score
0

Homework Statement



Prove that if b is a positive number, such that a < b, then
a/b<(a+1)/(b+1)

2. The attempt at a solution

I have tried a few things, attempting to prove it using the real line, and a bunch of other methods but have had no success. I Would greatly appreciate it if u can at least get me started.
 
Physics news on Phys.org
John H said:

Homework Statement



Prove that if b is a positive number, such that a < b, then
a/b<(a+1)/(b+1)

2. The attempt at a solution

I have tried a few things, attempting to prove it using the real line, and a bunch of other methods but have had no success. I Would greatly appreciate it if u can at least get me started.

Clear out the fractions, i.e. multiply both sides by the common denominator. You didn't try that?
 
I did before, but I made the most retarded mistake of thinking a(b+1)=b(a+1). Sorry about that. Thanx
 
a<b. You can add any number to both sides of an inequality, it stays valid. Why not trying to add ab?

ehild
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top