Proving Inequality using Mean Value Theorem

frankpupu
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Homework Statement



Use the Mean Value Theorem to prove that if p>1.then ((1+x)^p)>(1-px) for x in (-1,0)and(0,infinite)

i have no idea that what's the relationship between the inequality and the theorem? first i define g(X)=((1+x)^p)-(1-px) then for x=0 f(0)=0.i.e. x not equals to 0,which x is in(-1,0)and(0,infinite), then i don't know how to do next ,i think is that one case for x>0 ,the other is for -1<x<0, then use theorem to prove g(X)>0 can someone give me some idea?
 
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frankpupu said:

Homework Statement



Use the Mean Value Theorem to prove that if p>1.then ((1+x)^p)>(1-px) for x in (-1,0)and(0,infinite)

i have no idea that what's the relationship between the inequality and the theorem? first i define g(X)=((1+x)^p)-(1-px) then for x=0 f(0)=0.i.e. x not equals to 0,which x is in(-1,0)and(0,infinite), then i don't know how to do next ,i think is that one case for x>0 ,the other is for -1<x<0, then use theorem to prove g(X)>0 can someone give me some idea?

It isn't true if ##p=2## and ##x=-1/2##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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