Proving integration of arcsinx

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To prove the integral of arcsin(x), start by differentiating with x = sin(y) and applying a trigonometric identity to express cosine in terms of sine. This leads to the derivative of y = arcsin(x). For the integral, integrating by parts is suggested, with u = arcsin(x) and dv = dx. The discussion emphasizes the need for clarity in problem statements and questions the appropriateness of posting calculus problems in a precalculus section. Clear communication and proper categorization are essential for effective assistance.
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proving for intge of (arcsinx) .

pls help...thanx
 
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Start with x = sin y

Differentiate. Use a trig identity to express the cos you get in terms of the original function (sine). Rewrite that replacing the sin y's with x's.

Edit: Whoops, nevermind. That will give you the deriviative of y = arcsin x, eventually. It looks like you want the integral of arcsinx, but I can't be sure. If you want help, you really should state the problem more clearly than you have.
 
teng125 said:
proving for intge of (arcsinx) .
pls help...thanx
This is posted under homework help but you have not shown what you have already tried yourself.
 
\int \arcsin (x) dx.
Looking at that integral, you have no idea how to begin it, then the most common thing to do is to use integrating by parts. What's u, and what's dv, you think?
 
Well, there's only one function and you don't know immediately how to integrate it (that's the whole problem!) so how about trying
u= arcsin(x), dv= dx?

By the way, is there a reason for posing problems about derivatives and integrals in the precalculus section?
 
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