Proving Isometry on Metric: How to Do It

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How do I prove every isometry from R->R is of the form f(x)=a+-x , regardless of the metric?

I know it has to do with considering d_1(0,x_1)=d_2(0, f(x_1)), but beyond that I am lost.
 
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Start by writing out the definition of "isometry"!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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