Proving Locus of Middle Points of Chords on Parabola

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The discussion revolves around proving that the locus of the midpoints of all chords of the parabola y^2=4ax, drawn through the vertex, forms the parabola y^2=2ax. The midpoint of a chord connecting the vertex to a point on the parabola is expressed as (h/2, √(ah)). Participants suggest eliminating the variable h to derive the equation of the locus. There is a moment of realization about a previous misunderstanding in the approach. The conversation highlights the importance of correctly manipulating the equations to reach the desired conclusion.
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Homework Statement


Prove that the locus of middle points of all chords of the parabola ##y^2=4ax## which are drawn through the vertex is the parabola ##y^2=2ax##.


Homework Equations





The Attempt at a Solution


The mid-point of the line joining the vertex and a point ##(h,2\sqrt{ah})## on parabola is ##(h/2,\sqrt{ah})## but what am I supposed to do with this? :confused:
 
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Pranav-Arora said:

Homework Statement


Prove that the locus of middle points of all chords of the parabola ##y^2=4ax## which are drawn through the vertex is the parabola ##y^2=2ax##.


Homework Equations





The Attempt at a Solution


The mid-point of the line joining the vertex and a point ##(h,2\sqrt{ah})## on parabola is ##(h/2,\sqrt{ah})## but what am I supposed to do with this? :confused:

You have ##x=h/2## and ##y=\sqrt{ah}##. Eliminate h?
 
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I like Serena said:
You have ##x=h/2## and ##y=\sqrt{ah}##. Eliminate h?

Woops, I was trying this question from the last night and I couldn't even notice that. Very foolish of me. :redface:

Thank you ILS! :smile:
 
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