Proving Perpendicularity of FE & AB in a Semicircle

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To prove that line FE extended is perpendicular to diameter AB in a semicircle, it is essential to utilize the properties of right triangles ACB and ADB, which have right angles at points C and D on the arc. The proof can be simplified by applying analytical geometry rather than classical methods, which may involve identifying congruent triangles. The intersection point E of lines AD and BC plays a crucial role in establishing the relationship between the angles formed. By demonstrating that the angles at E are complementary, the perpendicularity of FE to AB can be confirmed. This approach effectively clarifies the geometric relationships within the semicircle.
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AB is the diameter of a semicircle. Points C and D are ANY two points on the arc of the semicircle. AD and BC intersect at E. AC and BD are extended to meet at F. Prove that FE extended is perpendicular to AB.

I need any help possible because i have no idea of how to solve this proof problem! pleasezzzzzzzzzzzzz
 
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The assertion is fairly easy to prove if you rephrase it in the terms of analytical geometry.
It looks difficult to prove it by "classical" means (i.e. identifying congruent triangles and suchlike)
 
Use the fact that triangles ACB and ADB are right triangles with right angle at C and D.
 
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