Proving Series Equations: A General Method

glebovg
Messages
156
Reaction score
0
How to prove (not by induction)

1^{2}+2^{2}+\ldots+n^{2}=\frac{n(n+1)(2n+1)}{6}?

What is the general approach for similar series, say, 1^{1}+2^{2}+\ldots+n^{n}?
 
Physics news on Phys.org
glebovg said:
How to prove (not by induction)

1^{2}+2^{2}+\ldots+n^{2}=\frac{n(n+1)(2n+1)}{6}?

What is the general approach for similar series, say, 1^{1}+2^{2}+\ldots+n^{n}?

For your first question, the sum is the solution to the difference equation S(n)-S(n-1)=n^2 subject to the initial condition S(1)=1. Since the difference is 2nd order polynomial, the solution is 3rd order polynomial, now you know how to proceed. For your second question, since the difference is n^n, no known simple function of n has such difference, therefore no simple solution.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top