Proving Set Theory Equation: Subsets of Size m = Subsets of Size n-m

TalonStriker
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Homework Statement



Prove that, for all n, for all m with 0 <= m <= n, the number of subsets of {1, . . . , n} of size m is the same as the number of subsets of {1, . . . , n} of size n − m.


Homework Equations


n/a


The Attempt at a Solution


My problem is that I don't know where to begin. I have a vague notion that I should somehow find the powerset of all the sets of size m and n - m and compare their sizes. But I don't really know where to start.
 
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Combinations?
 
C(n,m)=C(n,n-m) since order of elements in a set is not important.
 
EnumaElish said:
Combinations?

I am not familiar with combinations... what are they?

A google search doesn't net me any useful results.
 
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I want to choose m things. Therefore, I don't choose how many things?
 
If A is a subset of S= {1, 2,... n} with m members, how many members does S\A have? Do you see an obvious one-to-one correspondence?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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