Proving Statements for Field Math: F/b = (ab^-1) and Other Equations

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The discussion focuses on proving several mathematical statements related to field operations, specifically the expression a/b = ab^-1. Participants express confusion about the notation, particularly the meaning of the dashes and whether they indicate inverses or alternative values. The first statement is explored in detail, with attempts to manipulate the equation to show equivalence between a/b and a'/b'. Clarifications are sought regarding the interpretation of the operations involved, particularly whether ab^-1 refers to a multiplied by the inverse of b or the inverse of the product of a and b. The conversation emphasizes the need for a clear understanding of field properties to successfully prove the statements.
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Homework Statement


Let F be a field. For any a,b \in F, b\neq0, we write a/b for ab^-1. Prove the following statements for any a, a' \inF and b, b' \in F\{0}:

i.) a/b = a'/b' if and only if ab' =a'b
ii.) a/b +a'/b' = (ab'+a'b)/bb'
iii.) (a/b)(a'/b') = aa'/bb'
iv.) (a/b)/a'/b') = ab'/a'b (if in addition a'\neq0)


Homework Equations





The Attempt at a Solution



I'm struggling to understand how i am to prove these statements. What am i to take the dashes to mean, because they are often used to show inverses? So for the first one:

a/b=ab^-1 which = a^-1b = a'/b'?
 
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My guess is a dash means "alternative value." For example, a = 1, and a' = 2.
 
EnumaElish said:
My guess is a dash means "alternative value." For example, a = 1, and a' = 2.

I also thought that, i will go with that and see what i come up with, thanks
 
EnumaElish said:
My guess is a dash means "alternative value." For example, a = 1, and a' = 2.

Does ab^-1 mean a.b^-1 or (a.b)^-1? I think it might be the former.

If it is, i get:

i) a.b^-1 = a'.b'^-1 when written out fully. So if ab' = a'b, then rearranged gives a= a'b/b' and a' = ab'/b. So inserting them into a.b^-1 = a'.b'^-1 we get:

a'b.b^-1/b' = ab.b^-1/b

and then we get indentity elements leaving a'/b' = a/b

Is this right?
 
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