Proving that the det of the Lorentz tensor is +1 or -1 (MTW p 89)

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I have spent much effort trying to prove that det|\Lambda\mu\upsilon| = +1 or -1 (following a successful effort to prove (3.50g) on p87 of MTW)

From the result of \LambdaT\eta\Lambda = \eta I've produced four equations like:

\Lambda00\Lambda00 - \Lambda01\Lambda01 - \Lambda02\Lambda02 - \Lambda03\Lambda03 = 1

and six like:

- \Lambda00\Lambda10 - \Lambda01\Lambda11 - \Lambda02\Lambda12 - \Lambda03\Lambda13 = 0

I was hoping that by various combinations of products of these equations I would be able to find all the terms needed to produce det|\Lambda\mu\upsilon|2 but I end up with a large number of terms so of which look to be OK plus lots of terms which I need to eliminate and can't. It is also very messy!

Is there an elegant way of doing this?


TerryW
 
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##\det(\Lambda^{T}\eta \Lambda) = \det(\eta)\det(\Lambda^{T})\det(\Lambda) = \det(\eta)\\ \Rightarrow (\det(\Lambda))^{2} = 1\Rightarrow \det(\Lambda) = \pm 1##
 
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