Proving the Bounded Linearity of A in l^{p} Space

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Homework Statement


Let 1\leqp\leq\infty and suppose (\alpha_{ij} is a matrix such that (Af)(i)=\sum^{\infty}_{j=1}\alpha_{ij}f(j) defines an element Af of l^{p} for every f in l^{p}. Show that A is a bounded linear functional on l^{p}


Homework Equations


Isn't this obvious if we apply theorem that says following are equivalent for A:X-->X a linear transformation on normed space?
(a)A is bounded linear functional
(b)A is continuous at some point
(c)There is a positive constant c such that ||Ax||\leqc||x|| for all x in X.


The Attempt at a Solution


Isn't the contiunuity of f obvious? So by the theorem, I think A is bounded linear functional on l^{p}. Could you guys correct me if I am wrong? Or if I am right could you just say it is right?

Thanks
 
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Er, the continuity of f? f is an element of l^p, not a function. Also, how is A a functional on l^p? To me a functional on X is a mapping into the scalar field, and I believe this is standard terminology; A looks like a mapping from l^p to l^p (namely f \mapsto Af).

Edit:
Looking at what you said again, I think you might've meant to say "continuity at f". If so, what f?
 
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Maybe then I should say that A is bounded linear transformation?
But still isn't continuity of A obvious by construction?
 
Why is it obvious? Can you post your proof?
 
Sorry. It's not obvious. It seems continuous though.
I know for given epsilon > 0, I need to find delta>0 such that ||f||<delta implies
||Af||<epsilon. Hmm.. How can I find such delta? Or use cauchy sequence?
 
It's not that it's a difficult problem, but I just wouldn't say that the continuity of A is obvious. Anyway, I would use characterization (c) in the first post. Namely, try to compute ||Ax||_p given an arbitrary sequence x=(x_1, x_2, ...) in l^p. It will help to split this into three cases, depending on whether p=1, 1<p<\infty, or p=\infty. Holder's inequality (and Cauchy-Schwarz) will be helpful in the first two cases.

If you need any more hints, post back.

Also, a much more interesting (and more difficult!) problem is to prove that the same map, x \mapsto Ax, is continuous if it maps sequence in l^p to sequences in l^p', where 1 < p, p' < \infty. You might want to try to tackle this one if you're looking for a challenge.
 
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